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No wisdom here, we all know this: 4 × 2 = 8. But if we look at this as a multiplication of fractions – we see that bigger numerators make our product bigger. So numerators "help" a product "grow". What happened with our number 4? Our 2/1 has made our 4/1 two times bigger, i.e. 8.
Second case of
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× | = | ||||||||||
4 | × | 1 | = | 4×1 | = | 4 | = 2 | ||||
1 | 2 | 1×2 | 2 |
Aha, now instead of making it bigger, it made our product smaller.
We’re noticing:
So we proudly conclude – if we’re multiplying by a fraction, i.e. a fraction is our multiplier, its numerator increases the product by multiplying the multiplicand, and a denominator decreases the product by dividing the multiplicand. What a mouthful!
Or we could simply put: multiplying by a fraction is like doing two operations at once – we’re multiplying by a numerator and dividing by a denominator (I like this one better).
Let’s try with second numerator > 1: We can interpret the case below as: what are the 2/5 of a 3
× | = | = | ||||||||||||
3 | × | 2 | = | 3×2 | = | 6 | = |
1 |
1 | |||||
1 | 5 | 1×5 | 5 | 5 |
So, we have 3 (wholes) and we’re multiplying it by 2 and dividing it by 5 at the same time (i.e. by 2/5). It’s a combined operation we could say. :-)
If we separate it in steps:
We can divide 6 by 5 but we would get a decimal number, and we’re not dealing now with decimals, so we’re leaving it as is.
So you see, this multiplying fractions with whole numbers is easy.
× | = | |||||||||
4 | × | 3 | = | 4×3 | = | 3 | ||||
1 | 4 | 1×4 | 1 |
But we should notice something, there’s no point in multiplying something by a number and then right away dividing it by that same number. So we reduce our product by eliminating the common factor 4 found above and below.
So that’s why I didn’t, and you never should, multiply 4×3 = 12, if you’re going to divide with that same 4 right afterwards.
Remember: |
Finally, we’re kickin’ out the whole numbers.
× | = | |||||||||
1 | × | 1 | = | 1×1 | = | 1 | ||||
2 | 2 | 2×2 | 4 |
We see that whatever’s down is making our product smaller. The proper question for the case above would be: what is the half of a half.
× | = | |||||||||
1 | × | 1 | = | 1×1 | = | 1 | ||||
4 | 3 | 4×3 | 12 |
In this case we’re asking: what is the third of one quarter. And if we divide 1/4 to 3 parts – we’ll get 1/12.
× | = | |||||||||
2 | × | 4 | = | 2×4 | = | 8 | ||||
3 | 5 | 3×5 | 15 |
In this case above we’re wondering what are the four fifths of two thirds.
In this next case we’ll throw in some reducing
× | = | |||||||||
3 | × | 4 | = | 3×4 | = | 1 | ||||
4 | 6 | 4×3×2 | 2 |
We factored 6 to 3×2. We do not necessarily have to factor every number to primes, the moment we spot common factors above and bellow the line – we reduce.
Well, the first thing we should do when want to multiply mixed fractions is – not to do it. :-)
We should turn that mixed fractions multiplication into an improper fraction multiplication. I.e. we turn our mixed fractions into improper fractions.
Say we have this problem:
× | = ? | ||||||
1 |
4 | × |
2 |
1 | = ? | ||
6 | 4 |
As we said, we’re going to turn both of them into the improper form using the following formula:
Improper Numerator = = (Denominator × Number of Wholes) + + Mixed Numerator |
And when we apply that to our first mixed fraction we get this:
= | ||||||
1 |
4 | = | 1×6 + 4 | = | 10 | |
6 | 6 | 6 |
We could have reduced but we're not going to, for the sake of practicing we're saving it for multiplication.
And here it is for the second mixed fraction.
= | ||||||
2 |
1 | = | 2×4 + 1 | = | 9 | |
4 | 4 | 4 |
Phew! Finally we’re in business! Now, as usual, we factor to find as many common factors for reducing.
× | = | = | ||||||||||||
10 | × | 9 | = | 5×2×3×3 | = | 15 | = |
3 |
3 | |||||
6 | 4 | 3×2×4 | 4 | 4 |
We factored:
Please, DO NOT ever multiply if you have a chance to reduce!
One must admit that 15/4 is a much more elegant solution than 90/24. :-)
Conclusion
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